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Question

A block of mass 10 kg lies on a rough plane as shown in the figure. A constant force F is applied for 10 seconds, find out the value of work done by the force F.


A
12000 J
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B
10000 J
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C
6000 J
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D
0 J (because friction is present)
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Solution

The correct option is A 12000 J
FBD of Block
Net force in vertical direction
Nmg=0
N=mg=10×10=100 N

Frictional force =μN
=0.2×100
=20 N

Net force in horizontal direction
=FFrictional force
ma=6020
a=4010=4 m/s2
Applying ,
s=ut+12at2=0+12×4×102
s=200 m
Work done by force W=F.s=60×200
=12000 J

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