A block of mass 100 gm slides on a rough horizontal surface. If the speed of the block decreases from 10 m/s to 5 m/s, the thermal energy developed in the process is
A
3.75 J
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B
37.5 J
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C
0.375 J
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D
0.75 J
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Solution
The correct option is A3.75 J Thermal energy developed = Loss in kinetic energy =12m(ν22−ν21)=12×0.1×(102−52)=3.75J