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Standard XII

Physics

Net Force

A block of ma...

Question

A block of mass $1000 k g$ lying steady on the horizontal surface of a table needs $200 N$ horizontal force to came into motion. What is the coefficient of static friction between the block and the surface of table?
[take $g = 10 {m s}^{- 2}$ ]

0.2

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0.02

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0.5

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0.05

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Solution

The correct option is B $0.02$
frictional force= $μ m g$
$200 = μ 1000 \times 10$
$μ = 0.02$

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A block of mass 1000 kg lying steady on the horizontal surface of a table needs 200 N horizontal force to came into motion. What is the coefficient of static friction between the block and the surface of table? [take g=10ms−2]

The correct option is B 0.02frictional force=μmg200=μ1000×10μ=0.02

A block of mass $1000 k g$ lying steady on the horizontal surface of a table needs $200 N$ horizontal force to came into motion. What is the coefficient of static friction between the block and the surface of table?
[take $g = 10 {m s}^{- 2}$ ]

The correct option is B $0.02$
frictional force= $μ m g$
$200 = μ 1000 \times 10$
$μ = 0.02$