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Standard XII

Physics

Range on an Incline

A block of ma...

Question

A block of mass $12 K g$ is attached to a string wrapped around a wheel of radius $10 c m$ . The acceleration of the block moving down an inclined plane is measured as $2 m / s^{2}$ . The tension in the string is :

24.5 N

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68.7 N

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23.4 N

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46.8 N

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Solution

The correct option is B $46.8 N$
The acceleration of the block A: $a = (m g sin θ - T) / m$
$∴ T = m g sin θ - m a = 12 \times (10 sin 37^{0} - 2) = 12 \times (9.8 \times \frac{3}{5} - 2) = 46.56 N$

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A block of mass 12Kg is attached to a string wrapped around a wheel of radius 10cm. The acceleration of the block moving down an inclined plane is measured as 2m/s2. The tension in the string is :

The correct option is B 46.8 NThe acceleration of the block A: a=(mgsinθ−T)/m∴T=mgsinθ−ma=12×(10sin370−2)=12×(9.8×35−2)=46.56N

A block of mass $12 K g$ is attached to a string wrapped around a wheel of radius $10 c m$ . The acceleration of the block moving down an inclined plane is measured as $2 m / s^{2}$ . The tension in the string is :

The correct option is B $46.8 N$
The acceleration of the block A: $a = (m g sin θ - T) / m$
$∴ T = m g sin θ - m a = 12 \times (10 sin 37^{0} - 2) = 12 \times (9.8 \times \frac{3}{5} - 2) = 46.56 N$