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Question

A block of mass 15 kg is placed on a long trolley The coefficient of friction between the block and trolley is 0. 18 The trolley accelerates with 0.5 m/s2 for 20 s then what is the friction force

A
3.5 N
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B
133.3 N
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C
7.5 N
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D
N.O.T
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Solution

The correct option is B 7.5 N
Given;
Mass of the block m=15kg
Acceleration of the trolley a=0.5m/s2
As per newtons second law of motion the force on the block by the motion of the trolley is given by the relation:
F=ma
15×0.5=7.5N
Hence,
option (C) is correct answer.

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