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Question

A block of mass 15 kg is resting on a rough inclined plane as shown in figure. The block is tied up by a horizontal string which has a tension of 50 N. Calculate the coefficient of friction between the block and inclined plane. Consider g=10 ms2

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Solution

Since the string is under tension, there is limiting friction acting between the block and the plane.

Fx=050+μN cos 45 = N cos 45
(1μ)N2=50....(i)
Fy=0μNcos45+Ncos45=150
(1+μ)N2=150......(ii)
Equation (ii)/(i)1+μ1μ=15050
1+μ=33μ4μ=2μ=12

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