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Question

A block of mass 16 kg is moving on a frictionless horizontal surface with velocity 4m/s and comes to rest after pressing a spring. If the force constant of the spring is 100 N/m then the compression in the spring will be:

A
3.2 m
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B
1.6 m
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C
0.6 m
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D
6.1 m
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Solution

The correct option is B 1.6 m
1/2kx2=1/2mv2
1/2×100×x2=1/2×16×(4)2
50×x2=256/2
x2=128/50
x2=2.56
x=1.6
so, the spring is compressed 1.6m.
Hence,
option (B) is correct answer.

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