A block of mass 16kg is moving on a frictionless horizontal surface with velocity 4m/s and comes to rest after pressing a spring. If the force constant of the spring is 100N/m then the compression in the spring will be:
A
3.2m
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B
1.6m
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C
0.6m
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D
6.1m
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Solution
The correct option is B1.6m 1/2kx2=1/2mv2 1/2×100×x2=1/2×16×(4)2 50×x2=256/2 x2=128/50 x2=2.56 x=1.6 so, the spring is compressed 1.6m.