Question

A block of mass $2.00kg$ moving at a speed of $10.0\frac{m}{s}$ accelerates at $3.00\frac{m}{s^2}$ for 5.00 s. Compute its final kinetic energy?

• A. 625 J
• B. 25J
• C. 50 J
• D. 500 J

Answer 1

The correct option is A

625 J

$u=10\frac{m}{s},a=3\frac{m}{s^2},t=5s$

$V=u+at$

= $10+3\left(5\right)$

= $10+15$

= $25\frac{m}{s}$

$\therefore K.E.=\frac{1}{2}m{v}^2$

= $\frac{1}{2}\times 2\times {25}^2$

= ${25}^2$

= $625J$