A block of mass 2-00 kg moving at a speed of 10-0 m - s accelerates at 3-00 m - s 2 for 5-00 s- Compute its final kinetic energy-

Mass nbsp;of nbsp;the nbsp;block, nbsp;Mb=2 nbsp;kgInitial nbsp;speed nbsp;of nbsp;the nbsp;block, nbsp;u=10 nbsp;m/sAlso, nbsp;a=3 nb ...

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Standard IX

Physics

Kinetic Energy

A block of ma...

Question

A block of mass 2.00 kg moving at a speed of 10.0 m/s accelerates at 3.00 m/s² for 5.00 s. Compute its final kinetic energy.

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Solution

$Mass of the block, M_{b} = 2 kg Initial speed of the block, u = 10 m / s Also, a = 3 m / s^{2} and t = 5 s Using the equation of the motion, we have : ν = u + a t = 10 + 3 \times 5 = 25 m / s ∴ Final K . E . = \frac{1}{2} m ν^{2} = \frac{1}{2} \times 2 \times 625 = 625 J$

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A block of mass 2.00 kg moving at a speed of 10.0 m/s accelerates at 3.00 m/s2 for 5.00 s. Compute its final kinetic energy.

Mass of the block, Mb=2 kgInitial speed of the block, u=10 m/sAlso, a=3 m/s2 and t=5 sUsing the equation of the motion, we have:ν=u+at =10+3×5=25 m/s∴ Final K.E.=12mν2 =12×2×625=625 J

A block of mass 2.00 kg moving at a speed of 10.0 m/s accelerates at 3.00 m/s² for 5.00 s. Compute its final kinetic energy.

$Mass of the block, M_{b} = 2 kg Initial speed of the block, u = 10 m / s Also, a = 3 m / s^{2} and t = 5 s Using the equation of the motion, we have : ν = u + a t = 10 + 3 \times 5 = 25 m / s ∴ Final K . E . = \frac{1}{2} m ν^{2} = \frac{1}{2} \times 2 \times 625 = 625 J$