A block of mass $2.00 k g$ moving at a speed of $10.0 m / s$ accelerates at $3.00 m / s^{2}$ for $5.00 s$ . Compute its final kinetic energy.

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Solution

Given:
The mass of the block is $2.00 k g$ .
The acceleration of the block is $3 m / s^{2}$ .
The time for which the block accelerates is $5.00 s$ .

Final velocity of the block is given by:

$v = u + a t$

$v = 0 + 3 \times 5$

$v = 15 m / s$

Kinetic energy $= \frac{1}{2} \times m v^{2}$

$K . E = \frac{1}{2} \times 2 \times 15^{2}$

$K . E = 225 J$

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A block of mass 2.00 kg moving at a speed of 10.0m/s accelerates at 3.00m/s2 for 5.00 s. Compute its final kinetic energy.

Given:The mass of the block is 2.00 kg.The acceleration of the block is 3 m/s2.The time for which the block accelerates is 5.00 s.Final velocity of the block is given by: v=u+at v=0+3×5 v=15m/s Kinetic energy=12×mv2 K.E=12×2×152 K.E=225J

A block of mass $2.00 k g$ moving at a speed of $10.0 m / s$ accelerates at $3.00 m / s^{2}$ for $5.00 s$ . Compute its final kinetic energy.