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Question

A block of mass 2 kg collides with a horizontal mass-spring of force constant 2 Nm1.The block compresses spring 4 m from the rest position. Speed of the block at instant of collision is

A
16 m/s
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B
4 m/s
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C
8 m/s
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D
12 m/s
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Solution

The correct option is B 4 m/s
We know,
Loss in KE= gain in PE
12(2)(v)2=12Kx2
V2=12(2)(v)2
V=4m/s


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