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Question

A block of mass 2 kg collides with a horizontal massless spring of force constant 2 N/m. The block compresses the spring 4 cm from the rest position speed of the block at the instant of collision is in m/s

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Solution

Given,

Mass, m=2kg

Displacement, x=4cm=0.04m

Kinetic energy = potential energy of spring

12mv2=12kx2

v=kx2m=2×(0.04)22=0.04ms2

Hence, velocity before collision is 0.04ms1


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