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Question

A block of mass 2 kg is lying on a floor. The coefficient of friction is 0.4. If a force of 2.5 N is applied on the block as shown in the figure , then the magnitude of frictional force will be:
1068413_68ca94aa51864223aa16163a113c0f0c.png

A
7.5 N
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B
10 N
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C
2.5 N
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D
5 N
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Solution

The correct option is C 2.5 N
Given:
μ=0.4F=2.5 N
m=2 kg
N=mg=20 N
The max value of friction =μN=0.4×20=8 N
Since, the force applied is 2.5 N there is no need for friction to attain its max. value.
Frictional force =2.5 N
971920_1068413_ans_0584d92de27f44168df0ca44e63aab17.png

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