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Question

A block of mass 2 kg is placed on a rough inclined plane as shown in figure (μ=0.2) so that it just touches the spring. The block is allowed to move downwards. The spring will be compressed to a maximum of
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A
0.1 cm
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B
6.6 m
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C
1 cm
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D
13 cm
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Solution

The correct option is D 13 cm
The block keeps moving till its velocity becomes 0 again.
No KE, implies, total work done by all forces = 0
Work done by gravity + friction = Work done on spring (WNormal=0)
mgsinθxμmgcosθx=0.5kx2
x=2mg(sinθμcosθ)/k= 2(2x10)(1/2 - 0.23/2)/100
x=13cm

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