Question

A block of mass $2kg$ is placed on the floor. Force of $2.8N$ is applied to it. The coefficient of static friction is $0.4$. The force of friction between the block and the floor (taking $g=10m/s^2$) is

• A. $2.8N$
• B. $8N$
• C. $2N$
• D. Zero

Answer 1

The correct option is A $2.8N$

Force applied on block =2.8 N

maximum static friction force

$f_{max}=0.4\times 2\times 10=8N$

Since applied force is less maximum static friction force.

thus friction force is equal to applied force =2.8 N

Option A is correct.