A block of mass 2 kg is projected upwards along a 300 inclined plane with an initial velocity of 22 m/s. The coefficient of friction between the block and the plane is 0.2. The block moves up the plane to a distance of :
A
6.8 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
8.6 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
36.6 m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
86 m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B 36.6 m Stopping distance S=u22a a=gsinθ+μgcosθ =9.8×12+0.2×9.8×√32=6.6m/s2 Now S=u22a=22×222×6.6=36.6m