A block of mass $2$ kg is pushed against a rough vertical wall with a force of $40$ N, coefficient force of $15$ N, is applied on the block in a direction parallel to the wall.

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Solution

When a Force of $40 N$ is applied, It will be balanced by the Normal Reaction from the Wall.

When a Force of $15 N$ is applied, then It may cause Friction.

$F n e t = \sqrt [(15) ² + (20) ²]$

⇒ F (net) = √625

⇒ $F (n e t) = 25 N .$

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A block of mass $2 k g$ is pushed against a rough vertical wall with a force of $40 N$ , coefficient of static friction being $0.5$ . Another horizontal force of $15 N$ , is applied on the block in a direction parallel to the wall. Will the frictional force exerted by the wall on the block ?

Q. A block of mass 2 kg is pushed against a rough vertical wall with a force of 40 N, coefficient of static friction being 0.5. Another horizontal force of 15 N, is applied on the block in a direction parallel to the wall. Will the block move? If yes, in which direction? If no, find the frictional force exerted by the wall on the block.

Q. A block of mass

2 k g

is pushed normally against a rough vertical wall with a force of

40 N

, co-efficient of static friction being

0.5

. Another horizontal force of

15 N

is applied on the block in a direction parallel to the wall. (Will the block move? If yes, in which direction and with what minimum acceleration? If no, find the friction force exerted by the wall on the block.)

A block of mass 2 kg is pushed normally against a rough vertical wall with a force of 40 N, co-efficient of static friction being 0.5. Another horizontal force of 15 N is applied on the block in a direction parallel to the wall. Will the block move? If yes, in which direction and with what acceleration? If no, find the frictional force exerted by the wall on the block.

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A block of mass 2 kg is pushed against a rough vertical wall with a force of 40 N, coefficient force of 15 N, is applied on the block in a direction parallel to the wall.

When a Force of 40N is applied, It will be balanced by the Normal Reaction from the Wall. When a Force of 15N is applied, then It may cause Friction. Fnet=√[(15)²+(20)²] ⇒ F (net) = √625 ⇒ F(net)=25N.

A block of mass $2$ kg is pushed against a rough vertical wall with a force of $40$ N, coefficient force of $15$ N, is applied on the block in a direction parallel to the wall.

When a Force of $40 N$ is applied, It will be balanced by the Normal Reaction from the Wall.

When a Force of $15 N$ is applied, then It may cause Friction.

$F n e t = \sqrt [(15) ² + (20) ²]$

⇒ F (net) = √625

⇒ $F (n e t) = 25 N .$