A block of mass 2 kg is pushed down an inclined plane of inclination $37^{0}$ with a force of 20 N acting parallel to the incline. It is found that the block moves on the incline with an acceleration of 10 $m s^{- 2}$ . If the block started from rest, then
Find the work done by the applied force in the first second ?

50 J

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75 J

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100 J

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120 J

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Solution

The correct option is C 100 J
Given $:$
$m = 2 k g$
$θ = 37^{0}$
$F = 20 N$
$a = 10 m / s^{2}$
$t = 1 s e c$
$S o, s = u t + \frac{1}{2} a t^{2} = 5 m$
work done by the applied force $W = F S cos o^{o} = 20 \times 5 = 100 J$
Hence,
option $(C)$ is correct answer.

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Q. A block of mass

m

is moving down with constant velocity along an inclined plane of inclination

θ

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The correct option is C 100 JGiven:m=2kgθ=370F=20Na=10m/s2t=1secSo,s=ut+12at2=5mwork done by the applied force W=FScosoo=20×5=100JHence,option (C) is correct answer.

The correct option is C 100 J
Given $:$
$m = 2 k g$
$θ = 37^{0}$
$F = 20 N$
$a = 10 m / s^{2}$
$t = 1 s e c$
$S o, s = u t + \frac{1}{2} a t^{2} = 5 m$
work done by the applied force $W = F S cos o^{o} = 20 \times 5 = 100 J$
Hence,
option $(C)$ is correct answer.