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Question

A block of mass 2kg is sliding with a constant velocity of 8m/s on a frictionless horizontal surface. The force exerted on the horizontal surface is nearly :


A
20 N
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B
10 N
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C
40 N
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D
16 N
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Solution

The correct option is A 20 N
The FBD will be as
For equilibrium in vertical direction
Nmg=0
N=mg=(2)10=20 N
The normal contact force applied by the surface is 20 N, thus by Newton's third law of motion, 20 N force will be exerted by the block on the surface.
Option A is correct.

1424136_1067962_ans_01f8e0fe3a824e0b8863d67a3941232b.png

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