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Question

# A block of mass 2 kg slides down the face of a smooth 45o wedge of mass 9 kg as shown in the figure. The wedge is placed on a frictionless horizontal surface. Determine the acceleration of the wedge.

A
2 m/ s 2
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B
112 m/s 2
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C
1 m/ s 2
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D
None of these
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Solution

## The correct option is C 1 m/ s 2a is the acceleration of the block w.r.t the wedgeFor block:N+mAsin45o=mgcos45oSo, N=(2×10×1√2)−(2×A×1√2)N=10√2−A√2For wedge : Nsin45o=MAFrom Equation (i) and (ii)(10√2−A√2)×1√2=9×A10−A=9AA=1 m/s2

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