A block of mass $2 m$ moving with a velocity of $v$ collides with a bock of mass $4 c m$ which is rest. After collides first back comes into rest. Find the value of coefficient of restitution.

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Solution

From conservation of mass,
Final momentum = initial momentum
$2 m v + 0 = 0 + 4 m v_{2}$
$v_{2} = 0.5 v$
Coefficient of restitution,
$e = - \frac{v_{1} - v_{2}}{u_{1} - u_{2}}$
$e = - \frac{0 - 0.5 v}{v - 0} = 0.5$
Hence, coefficient of restitution is $0.5$ .

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A block of mass 2 m moving with a velocity of v collides with a bock of mass 4 cm which is rest. After collides first back comes into rest. Find the value of coefficient of restitution.

From conservation of mass,Final momentum = initial momentum2mv+0=0+4mv2v2=0.5vCoefficient of restitution,e=−v1−v2u1−u2e=−0−0.5vv−0=0.5Hence, coefficient of restitution is 0.5.

A block of mass $2 m$ moving with a velocity of $v$ collides with a bock of mass $4 c m$ which is rest. After collides first back comes into rest. Find the value of coefficient of restitution.

From conservation of mass,
Final momentum = initial momentum
$2 m v + 0 = 0 + 4 m v_{2}$
$v_{2} = 0.5 v$
Coefficient of restitution,
$e = - \frac{v_{1} - v_{2}}{u_{1} - u_{2}}$
$e = - \frac{0 - 0.5 v}{v - 0} = 0.5$
Hence, coefficient of restitution is $0.5$ .