A block of mass $2 m$ moving with constant velocity $3 \to v$ collides with another block of mass $m$ which is at rest and stick to it. The velocity of the compound block after collision is :

\to v

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3 \to v / 2

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2 \to v

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3 \to v

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Solution

The correct option is C $2 \to v$
Here, a block of mass $2 m$ moving with constant velocity $3 v$ collides with another block of mass $m$ which is at rest and stick to it hence,

$m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v$

$(2 m) (3 \to v) + m (0) = (2 m + m) v$

$6 m \to v = 3 m v$

$v = 2 \to v$

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A block of mass 2m moving with constant velocity 3→v collides with another block of mass m which is at rest and stick to it. The velocity of the compound block after collision is :

The correct option is C 2→vHere, a block of mass 2m moving with constant velocity 3v collides with another block of mass m which is at rest and stick to it hence,m1u1+m2u2=(m1+m2)v(2m)(3→v)+m(0)=(2m+m)v6m→v=3mvv=2→v

A block of mass $2 m$ moving with constant velocity $3 \to v$ collides with another block of mass $m$ which is at rest and stick to it. The velocity of the compound block after collision is :