A block of mass 2kg is put on a rough horizontal surface having coefficient of friction 0.5. The acceleration of block and frictional force acting on block if F=7N is (Take g=10m/s2)
A
72m/s2,10N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0m/s2,7N
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
0m/s2,10N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
5m/s2,5N
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B0m/s2,7N By the free body diagram,
Here the applied force is 7N, for the limiting frictional force
fmax=μN=0.5×20=10N,
here the applied force F<fmax and hence the block will not move and the friction is static in nature, f=7N