A block of mass 2kg slides down an incline plane of inclination 30∘. The coefficient of friction between block and plane is 0.5. The contact force between block and incline plane is :
A
25N
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B
10√3N
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C
5√7N
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D
5√15N
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Solution
The correct option is D5√15N Now FBD for the block N=mgcosθ=2×10×√32 N=10√3 f=μN =0.5×10√3 =5√3 Fnet=√N2+f2 =√300+75 =√375 =√15×25 =5√15N