A block of mass 20 kg moving at 2.0 m/s collides head on with another block of equal mass at rest. The maximum possible loss in kinetic energy due to the collision is:

1 J

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3 J

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2 J

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4 J

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Solution

The correct option is C
2 J

Loss is maximum in perfect inelastic collision loss of K.E. $= \frac{1}{2} \frac{m_{1} m_{2}}{m_{1} + m_{2}} (u_{1} - u_{2})^{2} = 20 J$

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A block of mass 20 kg moving at 2.0 m/s collides head on with another block of equal mass at rest. The maximum possible loss in kinetic energy due to the collision is:

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A block of mass 20 kg moving at 2.0 m/s collides head on with another block of equal mass at rest. The maximum possible loss in kinetic energy due to the collision is:

The correct option is C 2 J Loss is maximum in perfect inelastic collision loss of K.E. =12m1m2m1+m2(u1−u2)2=20J

The correct option is C
2 J

Loss is maximum in perfect inelastic collision loss of K.E. $= \frac{1}{2} \frac{m_{1} m_{2}}{m_{1} + m_{2}} (u_{1} - u_{2})^{2} = 20 J$