Question

A block of mass 250 g is kept on a vertical spring of spring constant 100 N/m fixed from below. The spring ' is a now compressed to have a length 10 cm shorter than . its natural length and the system is released from this position. how does the block rise ? Take $g=10m/s^2$

Answer 1

$m=250g=0.25kg,k=100N/m$

$x=10cm$

$=0.1m,$

$g=10m/se{c}^2,h=?$

Applying law of energy,

$\frac{1}{2}k{x}^2=mgh$

$\Rightarrow h=\frac{1}{2}\left(\frac{k{x}^2}{mg}\right)$

$=\frac{100\times 0.01}{2\times \left(0.250\right)\times 10}$

$=0.2m=20cm$