Question

A block of mass $2500kg$ has volume $5m^3$. Calculate its density in $kg{m}^{-3}$ and $gc{m}^{-3}$ ?

Answer 1

Step-1:Given

Mass of block, $m=2500kg=2500\times {10}^{3}g$

Volume of the block, $V=5m^3=5\times {10}^{6}c{m}^3$

Step-2: Formula

$Density\left(\rho \right)=\frac{mass\left(m\right)}{volume\left(V\right)}$

Step-3: Density of block

$$\begin{gathered} Density\left(\rho \right)=\frac{mass\left(m\right)}{volume\left(V\right)} \\ \Rightarrow \rho =\frac{2500kg}{5m^3} \\ \Rightarrow \rho =500\raisebox{1ex}{$kg$}\!\left/ \!\raisebox{-1ex}{$m^3$}\right. \end{gathered}$$

and

$$\begin{gathered} Density\left(\rho \right)=\frac{mass\left(m\right)}{volume\left(V\right)} \\ \Rightarrow \rho =\frac{2500\times {10}^{3}g}{5\times {10}^{6}c{m}^3} \\ \Rightarrow \rho =0.5\raisebox{1ex}{$g$}\!\left/ \!\raisebox{-1ex}{$c{m}^3$}\right. \end{gathered}$$

Hence, the density of block is $\rho =500\raisebox{1ex}{$kg$}\!\left/ \!\raisebox{-1ex}{$m^3$}\right.$ or $\rho =0.5\raisebox{1ex}{$g$}\!\left/ \!\raisebox{-1ex}{$c{m}^3$}\right.$.