A block of mass 250g slides down an incline of inclination 37 - with a uniform speed- Find the work done against the fiction as the block slides through 1 - 0m

Component of acceleration towards displacement = g sin37^0 = 3g5 = 6 m/s^2 Force in the direction of displacement , F= ma #160; #160; # ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Average and Instaneous Power

A block of ma...

Question

A block of mass $250 g$ slides down an incline of inclination $37^{\circ}$ with a uniform speed. Find the work done against the fiction as the block slides through $1 \cdot 0 m$

Open in App

Solution

Component of acceleration towards displacement $= g s i n 37^{0} = \frac{3 g}{5} = 6 m / s^{2}$
Force in the direction of displacement , $F = m a$
$= 0.25 \times 6$
$= 1.5 N$

Work done against the friction , $W = F s = 1.5 \times 1 = 1.5 J$

Suggest Corrections

Similar questions

Q. A block of mass

250 g

slides down an incline of inclination

37^{0}

with a uniform speed. Find the work done against the friction as the block slides through

1.0 m

A block of mass 250 g slides down an incline of inclination $37^{\circ}$ with a uniform speed. Find the work done against the friction as the block slides through 1.0 m.

Q. A block of mass

500 g

slides down a a rough incline plane of inclination

53^{o}

with a uniform speed. Find the work done against the friction as the block slides through

2 m

[g = 10 m / s^{- 2}]

Q. A block of mass 500 g slides down on a rough incline plane of incline plane of inclination 53 with a uniform speed. Find the work done against the friction as the block slides through 2 m.

[g = 10 m / s^{2}]

Q. A block of mass 1 kg slides down on an inclined plane with the angle of inclination of

30^{0}

. Find the work done as the block slides through 50 cm.

Join BYJU'S Learning Program

A block of mass 250g slides down an incline of inclination 37∘ with a uniform speed. Find the work done against the fiction as the block slides through 1⋅0m

Component of acceleration towards displacement =gsin370=3g5=6 m/s2Force in the direction of displacement , F=ma =0.25×6 =1.5NWork done against the friction ,W=F s=1.5×1=1.5 J

A block of mass $250 g$ slides down an incline of inclination $37^{\circ}$ with a uniform speed. Find the work done against the fiction as the block slides through $1 \cdot 0 m$

Component of acceleration towards displacement $= g s i n 37^{0} = \frac{3 g}{5} = 6 m / s^{2}$
Force in the direction of displacement , $F = m a$
$= 0.25 \times 6$
$= 1.5 N$

Work done against the friction , $W = F s = 1.5 \times 1 = 1.5 J$