A block of mass 2kg is released from the top of a rough incline of height 2m. If the velocity of the block on the reaching the bottom is 4m/s. Then find the magnitude of work done in juoles by the frictional force on the block. G=10m/s2.
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Solution
Using conservation of energy, mgh = 1/2 mv^2 + W(work done to overcome friction) 2×10×2 = 1/2 × 2 × 16 + W 40 = 16 + W W = 40 - 16 = 24 J