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Question

A block of mass 2kg rests on an inclined plane of inclination angle 37o, then calculate the force of friction acting on the block (take g=10m/s2)
693338_6814084118b4488fa0d060311e73fa87.png

A
20N
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B
12N
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C
16N
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D
Zero
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Solution

The correct option is B 12N
FBD of body is,
force of friction FU=NsinQ
Where Q is angle of inclination,
F=20sin37=12N

857404_693338_ans_b68d519de0e54ea4b26af04cd7cc612e.png

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