A block of mass 3 kg is placed on a rough horizontal surface(μs=0.4). A force of 8.7 N is applied on the block. If g=10ms−2, then the force of friction between the block and floor is:
A
8.7 N
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B
12 N
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C
10 N
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D
zero
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Solution
The correct option is A 8.7 N fman=μN=0.4×30=12fman>favfSo,f=fapplyf=8.7N