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Question

A block of mass 3 kg is placed on the floor of coefficient of static friction is 0.4. The force of 3.5 N applied on the block. Calculate the force of friction and discuss the motion of the body.

A
3.5 N, moves
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B
3.5 N, remains at rest
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C
11.76 N, moves
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D
11.76 N, remains at rest
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Solution

The correct option is B 3.5 N, remains at rest
block is placed on the horizontal plane, so mg=N
also maximum friction force is μ.N=0.4×3×10=12 N.
but friction force acts only if there is a tendency of motion. so friction force will be equal to force applied until it reaches its maximum value. After that limiting friction will act and body will start moving.
So 3.5<12, hence friction acting is 3.5 N and body will not move.

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