A block of mass $30 k g$ is resting on a smooth surface. Forces of $600 N$ and $300 N$ act in north and south direction respectively. The magnitude and direction of acceleration of the block is

$14 m / s^{2}$ in north direction

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$18 m / s^{2}$ in east direction

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$10 m / s^{2}$ in south direction

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$10 m / s^{2}$ in north direction

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Solution

The correct option is D
$10 m / s^{2}$ in north direction

Given mass $m$ = $30 k g$

Force in north direction $f_{1}$ = $600 N$

Force in south direction $f_{2}$ = $300 N$

Net force acting = $f_{1} - f_{2}$ = $m a$

$\Rightarrow 600 N - 300 N$ = $30 a$

$\Rightarrow a$ = $10 m / s^{2}$ in north direction

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