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Question

A block of mass 4 kg is kept on a rough horizontal surface as shown in figure. A horizontal force of 19.6 N is just able to slide the block (a) Find the coefficient of static friction. (b) If a force of 16 N acts then what is the frictional force acting on the block?

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A
(a) 0.5 (b) 3.6N
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B
(a) 1.5 (b) 3.6N
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C
(a) 0.5 (b) 4.6N
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D
(a) 1.5 (b) 4.6N
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Solution

The correct option is A (a) 0.5 (b) 3.6N
Ff=m×0

f=19.6=μN

19.6=μ(4g)

μ=19.64×9.8=0.5

b) if another forceF of 16 N is applied;

FFf=0

19.616f=0

f=3.6N

977498_517092_ans_2121ecb179e94878a715b087bea6aed3.png

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