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Question

# A block of mass 4 kg is kept on a rough horizontal surface as shown in figure. A horizontal force of 19.6 N is just able to slide the block (a) Find the coefficient of static friction. (b) If a force of 16 N acts then what is the frictional force acting on the block?

A
(a) 0.5 (b) 3.6N
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B
(a) 1.5 (b) 3.6N
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C
(a) 0.5 (b) 4.6N
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D
(a) 1.5 (b) 4.6N
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Solution

## The correct option is A (a) 0.5 (b) 3.6NF−f=m×0f=19.6=μN19.6=μ(4g)μ=19.64×9.8=0.5b) if another forceF′ of 16 N is applied;F−F′−f=019.6−16−f=0f=3.6N

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