Question

A block of mass $4kg$ is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is $0.8$.The lorry is moving with an acceleration of $15m/s^2$ .The force of friction between lorry and block is $(g=10m/s^2)$

• A. $48N$
• B. $24N$
• C. $40N$
• D. $Zero$

Answer 1

The correct option is A $48N$

The friction force between the lorry and block is given as,

$F=\mu ma$

$=0.8\times 4\times 15$

$=48N$

Thus, the friction force between the lorry and block is $48N$.