A block of mass 4kg is placed in contact with the front vertical surface of a lorry. The coefficient of friction between the vertical surface and block is 0.8 .The lorry is moving with an acceleration of 15 m/s2 .The force of friction between lorry and block is (g=10m/s2)
The friction force between the lorry and block is given as,
F=μma
=0.8×4×15
=48N
Thus, the friction force between the lorry and block is 48N.