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Question

A block of mass 4 kg is placed on a rough horizontal plane. A time dependent force F=kt2 acts on the block. where k=2 N/s2. Coefficient of friction μ=0.8 . Force of friction between block and the plane at t=2 s is

A
8 N
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B
4 N
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C
2 N
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D
32 N
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Solution

The correct option is A 8 N
fmax=μ mg=0.8×4×10=32 N
At t=2 s,F=kt2=(2)(2)2=8 N
Since applied force F<fmax, force of friction will be the applied force itself which is 8 N

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