A block of mass 4kg is placed on a rough horizontal plane. A time dependent force F=kt2 acts on the block. where k=2N/s2. Coefficient of friction μ=0.8 . Force of friction between block and the plane at t=2s is
A
8N
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B
4N
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C
2N
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D
32N
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Solution
The correct option is A8N fmax=μmg=0.8×4×10=32N At t=2s,F=kt2=(2)(2)2=8N Since applied force F<fmax, force of friction will be the applied force itself which is 8N