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Question

A block of mass 4kg is placed on a rough horizontal plane. A time dependent force F=Kt2 acts on a block. where k=2Ns2, coefficient of friction =0.8. Force of friction between the block and the plane at t=2 S is:

A
32 N
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B
4 N
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C
2 N
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D
8 N
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Solution

The correct option is A 32 N
F=kg2
At t = 2 sec F=2×4
F=8N
F < friction
Friction = 8N
f=μmg=0.8×4×10
=32N

1150671_1102930_ans_0df4047e94404496bde6725084c9e5cd.png

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