A block of mass 4kg is pressed against the wall by a force of 80N as shown in figure. Determine the value of friction force and acceleration of block respectively. (Take coefficient of static friction 0.2, coefficient of kinetic friction 0.15)
A
8N,0m/s2
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B
32N,6m/s2
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C
8N,6m/s2
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D
32N,2m/s2
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Solution
The correct option is A8N,0m/s2 The FBD of the block is as shown in the figure.
From the FBD, N=80cos37∘=64N So, fL=μN=0.2×64=32N
In vertical direction, as mg<80sin37∘, friction force f will act downwards.
Net applied force in upward direction (excluding friction force) is 80sin37∘−40=48−40=8N As Fapplied in vertical direction is less than fL, block will not move in vertical direction and value of static friction force will be, f=8N