A block of mass 4kg is placed on a rough horizontal plane. A time depedent force F=kt2 acts on the block, where k=2N/s2. Coefficient of static friction μ=0.8. Force of friction between the block and the plane at t=2s is
A
8N
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B
4N
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C
2N
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D
32N
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Solution
The correct option is A8N fmax=μmg=0.8×4×10=32N
At t=2s, F=kt2=(2)(2)2=8N
Since applied force ft=2<fmax, block will be at rest and force of friction will be applied force at t=2s which is 8N