A block of mass 4kg hangs from a spring of spring constant k = 400 N/m. The block is pulled down through 15 cm below and released. What is the kinetic energy when the block is 10 cm above the equilibrium position?
The correct option is D 2.5J
Amplitude = 0.15 m
w=√km=√4004=10 rad/s⇒f=w2π=5π Hz
Energy of the particle executing SHM = KE + PE