.A block of mass 5.0 kg is suspended from the end of a vertical spring which is stretched by 10 cm under the load of the block. The block is given a sharp impulse from below so that it acquires an upward speed of 2.0 m/s. How high will it rise ? Take g = $10 m / s^{2}$

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Solution

$m = 5 k g, x = 10 c m = 0.1 m$

$v = 2 m / s e c, h = ?, g = 10 m . s e c^{2}$

So, $k = \frac{m g}{x}$

$= \frac{50}{0.1} = 500 N / m$

Total energy just the blow

$E = \frac{1}{2} m v^{2} + \frac{1}{2} k x^{2}$ ...(i)

Total energy at a height h

$= \frac{1}{2} h (h - x)^{2} - m g h$

On solving, we can get,

$h = 0.2 m$

$= 20 c m$

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.A block of mass 5.0 kg is suspended from the end of a vertical spring which is stretched by 10 cm under the load of the block. The block is given a sharp impulse from below so that it acquires an upward speed of 2.0 m/s. How high will it rise ? Take g = 10m/s2

m=5kg,x=10cm=0.1m v=2m/sec,h=?,g=10m.sec2 So, k=mgx =500.1=500N/m Total energy just the blow E=12mv2+12kx2 ...(i) Total energy at a height h =12h(h−x)2−mgh On solving, we can get, h=0.2m =20cm

.A block of mass 5.0 kg is suspended from the end of a vertical spring which is stretched by 10 cm under the load of the block. The block is given a sharp impulse from below so that it acquires an upward speed of 2.0 m/s. How high will it rise ? Take g = $10 m / s^{2}$