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Question
A block of mass 5.0 kg slides down an incline of inclination 30∘ and length 10 m. Find the work done by the force of gravity.
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Solution
Given:Mass of the block(m) = 5 kg.Distance covered by the block(S) = 10 m.Angle of Inclination(θ) = 30°
∵ Force (F) = Mass × Acceleration due to gravity.∴ Force = 5 × 9.8∴ Force = 49 N.
Using the Formula,
Work Done by the Force of Gravity = F.S. Sinθ
∴ W = 49 × 10 × Sin 30°⇒ W = 490 × 1/2 [ ∵ Sin 30° = 1/2]∴ W = 245 J.
Hence, the work done by the force of Gravity on the block is 245 J.
Given:
Mass of the block(m) = 5 kg.
Distance covered by the block(S) = 10 m.
Angle of Inclination(θ) = 30°
∵ Force (F) = Mass × Acceleration due to gravity.
∴ Force = 5 × 9.8
∴ Force = 49 N.
Using the Formula,
Work Done by the Force of Gravity = F.S. Sinθ
∴ W = 49 × 10 × Sin 30°
⇒ W = 490 × 1/2 [ ∵ Sin 30° = 1/2]
∴ W = 245 J.
Hence, the work done by the force of Gravity on the block is 245 J.
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