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Work Done by Force of Gravity

A block of ma...

Question

A block of mass $5 \cdot 0 k g$ slides down an incline of inclination $30^{o}$ and length $10 m$ . Find the work done by the force of gravity.

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Solution

Component of gravity acceleration, $a = g sin θ$

$W = F_{g} d = m g sin θ . d$

$W = 5 \times 10 sin 30^{o} .10 = 250 J$

Work done by gravity is $250 J$

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