MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Work Done by Force of Gravity

A block of ma...

Question

A block of mass $5 \cdot 0 k g$ slides down an incline of inclination $30^{o}$ and length $10 m$ . Find the work done by the force of gravity.

Open in App

Solution

Component of gravity acceleration, $a = g sin θ$

$W = F_{g} d = m g sin θ . d$

$W = 5 \times 10 sin 30^{o} .10 = 250 J$

Work done by gravity is $250 J$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A wooden block of mass

8

kg slides down an inclined plane of inclination

30^{o}

to the horizontal with constant acceleration

0.4 m / s^{2}

. The force of friction between the block and inclined plane is _____.

(g = 10 m / s^{2})

Q. A wooden block of mass

8

kg slides down an inclined plane of inclination

30^{o}

to the horizontal with constant acceleration

0.4 m / s^{2}

. The force of fiction between the block and inclined plane is

(g = 10 m / s^{2})

Q. A body of mass

25 kg

slides down a smooth incline as shown. Find the work done by force of gravity till the body reaches the bottom of the inclined plane (

g = 10 {ms}^{- 2}

Q. When a body of mass

m

slides down from the top of a smooth inclined plane of length

L

and inclination

θ

, the work done by the gravitational force on the body is (Given acceleration due to gravity

= g

Q. A block of mass 250 g slides down an incline of inclination 37° with uniform speed. Find the work done against friction as the block slides through 1m.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Work done by the force of gravity

PHYSICS

Watch in App

explore_more_icon

Explore more

Work Done by Force of Gravity

Standard X Physics

Join BYJU'S Learning Program

CrossIcon