Question

A block of mass $5kg$ is at rest on a rough inclined surface. If angle of inclination of plane is ${60}^o$. then force applied by it on block is:

• A. $50N$
• B. $25\sqrt{3}N$
• C. $25N$
• D. $50\sqrt{3}N$

Answer 1

The correct option is A $50N$

We need to find the resultant force between $mg\sin \theta$ and $mg\cos \theta$ which is actually $mg$ then $mg=(5\times 10)N=50N$.