Question

A block of mass 5 kg is at rest on the rough inclined surface. If the angle of inclination of the plane is 60 degree then force applied by it on the block is

Answer 1

Free body diagram:

From free body diagram, the force exerted by the inclined plane on the block is equal to the normal reaction N.

In equilibrium, $N=mgcos\theta$

Therefore, $Force=mgcos{60}^o$ $=5\times 9.8\times \left(\frac{1}{2}\right)=24.5N$.