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Question

A block of mass 5kg is initially at rest on a rough horizontal surface. A force of 45N acts on it in a horizontal direction and pushes it over a distance of 2m. The force of friction acting on the block is 25N. The final kinetic energy of the block is

A
40 J
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B
90 J
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C
50 J
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D
140 J
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Solution

The correct option is A 40 J
Using work-energy theorem:
W.Dforce+W.Dfriction=ΔK.E
45×225×2=KEfinal
KEfinal=40 J
55180_3516_ans.png

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