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Question

A block of mass 5 kg is lying on a rough horizontal surface. The coefficients of static and kinetic friction between the block and the surface respectively are 0.7 and 0.5. A horizontal force just sufficient to move the block is applied to it. If the force continues to act even after the block has started moving, what will be the acceleration of the block? Take g=10 ms2.


A

1 ms2

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B

2 ms2

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C

3 ms2

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D

4 ms2

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Solution

The correct option is B

2 ms2


Given m=5 kg,
μs=0.7 and
μk=0.5
Force required to just move the block = Limiting friction, i.e., F=μsmg=0.7×5×10=35 N
Now, once the block starts moving, kinetic friction will act on it. The accelerating force will be given by the difference of applied force and kinetic friction.
Fa=Fμkmg=350.5×5×10=3525=10 N
Acceleration, a=Fam=105=2 ms2
Hence, the correct choice is (b).


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