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Question

A block of mass 5kg is placed on a rough horizontal surface of a moving compartment. It is seen by an observer sitting inside the compartment, that a force of 10N is required in horizontal direction to move the box in a direction parallel to the motion of compartment while a force of 20N is required in horizontal direction to move the box in opposite direction. Find the coefficient of friction between the surface of the block and the surface.

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Solution

Here,
F1+ma=f ......................(1)

Again in oppoite direction;

F2=f+ma ......................(2)

From eq. (1) and (2);

F1+F2=2f

2f=20+10

f=15N

Also, f=μN=μ(mg)=μ(5×10)=μ(50)

μ(50)=15

μ=1550=0.3

979648_693787_ans_a8b84e3c0f0e4cabb885d1426266354d.png

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