A block of mass 5kg is kept on a horizontal floor having coefficient of friction 0.09. Two mutually perpendicular horizontal forces of 3 N and 4 N act on this block. The acceleration of the block is: (g=10m/s2)
A
Zero
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B
0.1m/s2
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C
0.2m/s2
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D
0.3m/s2
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Solution
The correct option is B0.1m/s2 Net external force F=√(4)2+(3)2=5N
Maximum friction fmax=μmg=(0.09)(5)(10)=4.5N
Since F>fmax, block will move with an acceleration, a=F−fmaxm=5−4.55=0.1m/s2